What are the solutions to the equation 6^2+11^2=x^2 ?

The solutions to the equation 6^2+11^2=x^2 are x=sqrt(157),x=-sqrt(157)

Find the zeros of 6^2+11^2=x^2

The zeros of 6^2+11^2=x^2 are x=sqrt(157),x=-sqrt(157)

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6^{2} + 1 1^{2} = x^{2}

x = 157, x = - 157

Decimal Notation

x = 12.52996 \dots, x = - 12.52996 \dots

Solution steps

6^{2} + 1 1^{2} = x^{2}

Switch sides

x^{2} = 6^{2} + 1 1^{2}

Simplify

6^{2} + 1 1^{2} : 157

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 157, x = - 157

k^{2} + 5 k - 14

n^{2} - 2 n + 1

27 m^{3} + 64 n^{9}

∣ x + 9 ∣ \geq 6

c^{2} + 2 c - 63

What are the solutions to the equation 6^2+11^2=x^2 ?
The solutions to the equation 6^2+11^2=x^2 are x=sqrt(157),x=-sqrt(157)
Find the zeros of 6^2+11^2=x^2
The zeros of 6^2+11^2=x^2 are x=sqrt(157),x=-sqrt(157)