What are the solutions to the equation 8z^2-2z-3=0 ?

The solutions to the equation 8z^2-2z-3=0 are z= 3/4 ,z=-1/2

Find the zeros of 8z^2-2z-3=0

The zeros of 8z^2-2z-3=0 are z= 3/4 ,z=-1/2

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8 z^{2} - 2 z - 3 = 0

z = \frac{3}{4}, z = - \frac{1}{2}

Decimal Notation

z = 0.75, z = - 0.5

Solution steps

8 z^{2} - 2 z - 3 = 0

Solve with the quadratic formula

z_{1, 2} = \frac{- ( - 2 ) \pm ( - 2 ) ^{2} - 4 \cdot 8 ( - 3 )}{2 \cdot 8}

(- 2)^{2} - 4 \cdot 8 (- 3) = 10

z_{1, 2} = \frac{- ( - 2 ) \pm 10}{2 \cdot 8}

Separate the solutions

z_{1} = \frac{- ( - 2 ) + 10}{2 \cdot 8}, z_{2} = \frac{- ( - 2 ) - 10}{2 \cdot 8}

z = \frac{- ( - 2 ) + 10}{2 \cdot 8} : \frac{3}{4}

z = \frac{- ( - 2 ) - 10}{2 \cdot 8} : - \frac{1}{2}

The solutions to the quadratic equation are:

z = \frac{3}{4}, z = - \frac{1}{2}

\frac{2}{5} (10 x + 15) = 26

15^{2}

7 x = 3 x - 24

x + x^{2} y^{2}

x^{2} - 8 x + 25 = 0

What are the solutions to the equation 8z^2-2z-3=0 ?
The solutions to the equation 8z^2-2z-3=0 are z= 3/4 ,z=-1/2
Find the zeros of 8z^2-2z-3=0
The zeros of 8z^2-2z-3=0 are z= 3/4 ,z=-1/2