What are the solutions to the equation 9(x+2)^2-4=2 ?

The solutions to the equation 9(x+2)^2-4=2 are x=sqrt(2/3)-2,x=-sqrt(2/3)-2

Find the zeros of 9(x+2)^2-4=2

The zeros of 9(x+2)^2-4=2 are x=sqrt(2/3)-2,x=-sqrt(2/3)-2

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9 (x + 2)^{2} - 4 = 2

x = \frac{2}{3} - 2, x = - \frac{2}{3} - 2

Decimal Notation

x = - 1.18350 \dots, x = - 2.81649 \dots

Solution steps

9 (x + 2)^{2} - 4 = 2

Move

4

to the right side

9 (x + 2)^{2} = 6

Divide both sides by

9

(x + 2)^{2} = \frac{2}{3}

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x + 2 = \frac{2}{3} : x = \frac{2}{3} - 2

Solve

x + 2 = - \frac{2}{3} : x = - \frac{2}{3} - 2

The solutions to the quadratic equation are:

x = \frac{2}{3} - 2, x = - \frac{2}{3} - 2

- 12 (x - 8) = 3 (x + 17)

125 - 300 n + 240 n^{2} - 64 n^{3}

30 a^{2} - 57 a - 45

- 3 < 1 - 2 n \leq 4

7 (- 4)

What are the solutions to the equation 9(x+2)^2-4=2 ?
The solutions to the equation 9(x+2)^2-4=2 are x=sqrt(2/3)-2,x=-sqrt(2/3)-2
Find the zeros of 9(x+2)^2-4=2
The zeros of 9(x+2)^2-4=2 are x=sqrt(2/3)-2,x=-sqrt(2/3)-2