What are the solutions to the equation 24s^2-s-3=0 ?

The solutions to the equation 24s^2-s-3=0 are s= 3/8 ,s=-1/3

Find the zeros of 24s^2-s-3=0

The zeros of 24s^2-s-3=0 are s= 3/8 ,s=-1/3

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24 s^{2} - s - 3 = 0

s = \frac{3}{8}, s = - \frac{1}{3}

Decimal Notation

s = 0.375, s = - 0.33333 \dots

Solution steps

24 s^{2} - s - 3 = 0

Solve with the quadratic formula

s_{1, 2} = \frac{- ( - 1 ) \pm ( - 1 ) ^{2} - 4 \cdot 24 ( - 3 )}{2 \cdot 24}

(- 1)^{2} - 4 \cdot 24 (- 3) = 17

s_{1, 2} = \frac{- ( - 1 ) \pm 17}{2 \cdot 24}

Separate the solutions

s_{1} = \frac{- ( - 1 ) + 17}{2 \cdot 24}, s_{2} = \frac{- ( - 1 ) - 17}{2 \cdot 24}

s = \frac{- ( - 1 ) + 17}{2 \cdot 24} : \frac{3}{8}

s = \frac{- ( - 1 ) - 17}{2 \cdot 24} : - \frac{1}{3}

The solutions to the quadratic equation are:

s = \frac{3}{8}, s = - \frac{1}{3}

(x - 7)^{2} = 20

- \frac{2 x}{5} = 8

\frac{a ^{2} + a}{2 a + 2}

\frac{2}{x} - 3 \leq 0

4 x^{2} - 12 x - 27

What are the solutions to the equation 24s^2-s-3=0 ?
The solutions to the equation 24s^2-s-3=0 are s= 3/8 ,s=-1/3
Find the zeros of 24s^2-s-3=0
The zeros of 24s^2-s-3=0 are s= 3/8 ,s=-1/3