What are the solutions to the equation 2u^2+2=-5u ?

The solutions to the equation 2u^2+2=-5u are u=-1/2 ,u=-2

Find the zeros of 2u^2+2=-5u

The zeros of 2u^2+2=-5u are u=-1/2 ,u=-2

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2 u^{2} + 2 = - 5 u

u = - \frac{1}{2}, u = - 2

Decimal Notation

u = - 0.5, u = - 2

Solution steps

2 u^{2} + 2 = - 5 u

Move

5 u

to the left side

2 u^{2} + 2 + 5 u = 0

Write in the standard form

a x^{2} + b x + c = 0

2 u^{2} + 5 u + 2 = 0

Solve with the quadratic formula

u_{1, 2} = \frac{- 5 \pm 5 ^{2} - 4 \cdot 2 \cdot 2}{2 \cdot 2}

5^{2} - 4 \cdot 2 \cdot 2 = 3

u_{1, 2} = \frac{- 5 \pm 3}{2 \cdot 2}

Separate the solutions

u_{1} = \frac{- 5 + 3}{2 \cdot 2}, u_{2} = \frac{- 5 - 3}{2 \cdot 2}

u = \frac{- 5 + 3}{2 \cdot 2} : - \frac{1}{2}

u = \frac{- 5 - 3}{2 \cdot 2} : - 2

The solutions to the quadratic equation are:

u = - \frac{1}{2}, u = - 2

x - 3 = - (x - 4)^{2} + 5

0.0004

\frac{\frac{3 !}{2 ! 1 !}}{3 6 ^{2}}

2 l + 2 w

8 \geq 11 + y

What are the solutions to the equation 2u^2+2=-5u ?
The solutions to the equation 2u^2+2=-5u are u=-1/2 ,u=-2
Find the zeros of 2u^2+2=-5u
The zeros of 2u^2+2=-5u are u=-1/2 ,u=-2