What are the solutions to the equation 3x^2+7x+1=0 ?

The solutions to the equation 3x^2+7x+1=0 are x=(-7+sqrt(37))/6 ,x=(-7-sqrt(37))/6

Find the zeros of 3x^2+7x+1=0

The zeros of 3x^2+7x+1=0 are x=(-7+sqrt(37))/6 ,x=(-7-sqrt(37))/6

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3 x^{2} + 7 x + 1 = 0

x = \frac{- 7 + 37}{6}, x = \frac{- 7 - 37}{6}

Decimal Notation

x = - 0.15287 \dots, x = - 2.18046 \dots

Solution steps

3 x^{2} + 7 x + 1 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 7 \pm 7 ^{2} - 4 \cdot 3 \cdot 1}{2 \cdot 3}

7^{2} - 4 \cdot 3 \cdot 1 = 37

x_{1, 2} = \frac{- 7 \pm 37}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- 7 + 37}{2 \cdot 3}, x_{2} = \frac{- 7 - 37}{2 \cdot 3}

x = \frac{- 7 + 37}{2 \cdot 3} : \frac{- 7 + 37}{6}

x = \frac{- 7 - 37}{2 \cdot 3} : \frac{- 7 - 37}{6}

The solutions to the quadratic equation are:

x = \frac{- 7 + 37}{6}, x = \frac{- 7 - 37}{6}

∣ x - 4 ∣ > 6

- 6 x^{2} + 5 x = 0

- 4 + 8 i

\frac{5 16}{3 12}

What are the solutions to the equation 3x^2+7x+1=0 ?
The solutions to the equation 3x^2+7x+1=0 are x=(-7+sqrt(37))/6 ,x=(-7-sqrt(37))/6
Find the zeros of 3x^2+7x+1=0
The zeros of 3x^2+7x+1=0 are x=(-7+sqrt(37))/6 ,x=(-7-sqrt(37))/6