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Popular >

u^2-27u+50=0

Solution

u^{2} - 27 u + 50 = 0

Solution

u = 25, u = 2

Solution steps

u^{2} - 27 u + 50 = 0

Solve with the quadratic formula

u_{1, 2} = \frac{- ( - 27 ) \pm ( - 27 ) ^{2} - 4 \cdot 1 \cdot 50}{2 \cdot 1}

(- 27)^{2} - 4 \cdot 1 \cdot 50 = 23

u_{1, 2} = \frac{- ( - 27 ) \pm 23}{2 \cdot 1}

Separate the solutions

u_{1} = \frac{- ( - 27 ) + 23}{2 \cdot 1}, u_{2} = \frac{- ( - 27 ) - 23}{2 \cdot 1}

u = \frac{- ( - 27 ) + 23}{2 \cdot 1} : 25

u = \frac{- ( - 27 ) - 23}{2 \cdot 1} : 2

The solutions to the quadratic equation are:

u = 25, u = 2

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Frequently Asked Questions (FAQ)

What are the solutions to the equation u^2-27u+50=0 ?
The solutions to the equation u^2-27u+50=0 are u=25,u=2
Find the zeros of u^2-27u+50=0
The zeros of u^2-27u+50=0 are u=25,u=2