What are the solutions to the equation 7a^2+32=7-40a ?

The solutions to the equation 7a^2+32=7-40a are a=-5/7 ,a=-5

Find the zeros of 7a^2+32=7-40a

The zeros of 7a^2+32=7-40a are a=-5/7 ,a=-5

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7 a^{2} + 32 = 7 - 40 a

a = - \frac{5}{7}, a = - 5

Solution steps

7 a^{2} + 32 = 7 - 40 a

Move

40 a

to the left side

7 a^{2} + 32 + 40 a = 7

Move

7

to the left side

7 a^{2} + 40 a + 25 = 0

Solve with the quadratic formula

a_{1, 2} = \frac{- 40 \pm 4 0 ^{2} - 4 \cdot 7 \cdot 25}{2 \cdot 7}

4 0^{2} - 4 \cdot 7 \cdot 25 = 30

a_{1, 2} = \frac{- 40 \pm 30}{2 \cdot 7}

Separate the solutions

a_{1} = \frac{- 40 + 30}{2 \cdot 7}, a_{2} = \frac{- 40 - 30}{2 \cdot 7}

a = \frac{- 40 + 30}{2 \cdot 7} : - \frac{5}{7}

a = \frac{- 40 - 30}{2 \cdot 7} : - 5

The solutions to the quadratic equation are:

a = - \frac{5}{7}, a = - 5

\frac{y ^{4}}{y ^{- 7}}

7 x + 28

- z - 3 = - 3 z^{2}

x^{2} + 31 = - 14 x - 9

- 4 \leq y \leq 1

What are the solutions to the equation 7a^2+32=7-40a ?
The solutions to the equation 7a^2+32=7-40a are a=-5/7 ,a=-5
Find the zeros of 7a^2+32=7-40a
The zeros of 7a^2+32=7-40a are a=-5/7 ,a=-5