What are the solutions to the equation x^2-2x+9=0 ?

The solutions to the equation x^2-2x+9=0 are x=1+2sqrt(2)i,x=1-2sqrt(2)i

Find the zeros of x^2-2x+9=0

The zeros of x^2-2x+9=0 are x=1+2sqrt(2)i,x=1-2sqrt(2)i

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x^{2} - 2 x + 9 = 0

x = 1 + 22 i, x = 1 - 22 i

Solution steps

x^{2} - 2 x + 9 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 2 ) \pm ( - 2 ) ^{2} - 4 \cdot 1 \cdot 9}{2 \cdot 1}

Simplify

(- 2)^{2} - 4 \cdot 1 \cdot 9 : 42 i

x_{1, 2} = \frac{- ( - 2 ) \pm 4 2 i}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 2 ) + 4 2 i}{2 \cdot 1}, x_{2} = \frac{- ( - 2 ) - 4 2 i}{2 \cdot 1}

x = \frac{- ( - 2 ) + 4 2 i}{2 \cdot 1} : 1 + 22 i

x = \frac{- ( - 2 ) - 4 2 i}{2 \cdot 1} : 1 - 22 i

The solutions to the quadratic equation are:

x = 1 + 22 i, x = 1 - 22 i

a^{2} - 8 a + 12

- 475 + 108

0.255 = \frac{x - 48}{15}

2 - 3 x \leq 6

\frac{1}{4} \cdot 20

What are the solutions to the equation x^2-2x+9=0 ?
The solutions to the equation x^2-2x+9=0 are x=1+2sqrt(2)i,x=1-2sqrt(2)i
Find the zeros of x^2-2x+9=0
The zeros of x^2-2x+9=0 are x=1+2sqrt(2)i,x=1-2sqrt(2)i