What are the solutions to the equation 0=3x^2-16x+21 ?

The solutions to the equation 0=3x^2-16x+21 are x=3,x= 7/3

Find the zeros of 0=3x^2-16x+21

The zeros of 0=3x^2-16x+21 are x=3,x= 7/3

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0 = 3 x^{2} - 16 x + 21

x = 3, x = \frac{7}{3}

Solution steps

0 = 3 x^{2} - 16 x + 21

Switch sides

3 x^{2} - 16 x + 21 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 16 ) \pm ( - 16 ) ^{2} - 4 \cdot 3 \cdot 21}{2 \cdot 3}

(- 16)^{2} - 4 \cdot 3 \cdot 21 = 2

x_{1, 2} = \frac{- ( - 16 ) \pm 2}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- ( - 16 ) + 2}{2 \cdot 3}, x_{2} = \frac{- ( - 16 ) - 2}{2 \cdot 3}

x = \frac{- ( - 16 ) + 2}{2 \cdot 3} : 3

x = \frac{- ( - 16 ) - 2}{2 \cdot 3} : \frac{7}{3}

The solutions to the quadratic equation are:

x = 3, x = \frac{7}{3}

4 x - (5 + 7 x) \leq 2 (x + 1)

- 5.39 - 13.4

- \frac{49}{0.7}

9 (y - 16) < - 63

- 5 \leq \frac{( 2 - 3 x )}{6} \leq 2

What are the solutions to the equation 0=3x^2-16x+21 ?
The solutions to the equation 0=3x^2-16x+21 are x=3,x= 7/3
Find the zeros of 0=3x^2-16x+21
The zeros of 0=3x^2-16x+21 are x=3,x= 7/3