What are the solutions to the equation 9x^2+6x+4=0 ?

The solutions to the equation 9x^2+6x+4=0 are x=-1/3+i(sqrt(3))/3 ,x=-1/3-i(sqrt(3))/3

Find the zeros of 9x^2+6x+4=0

The zeros of 9x^2+6x+4=0 are x=-1/3+i(sqrt(3))/3 ,x=-1/3-i(sqrt(3))/3

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9 x^{2} + 6 x + 4 = 0

x = - \frac{1}{3} + i \frac{3}{3}, x = - \frac{1}{3} - i \frac{3}{3}

Solution steps

9 x^{2} + 6 x + 4 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 6 \pm 6 ^{2} - 4 \cdot 9 \cdot 4}{2 \cdot 9}

Simplify

6^{2} - 4 \cdot 9 \cdot 4 : 63 i

x_{1, 2} = \frac{- 6 \pm 6 3 i}{2 \cdot 9}

Separate the solutions

x_{1} = \frac{- 6 + 6 3 i}{2 \cdot 9}, x_{2} = \frac{- 6 - 6 3 i}{2 \cdot 9}

x = \frac{- 6 + 6 3 i}{2 \cdot 9} : - \frac{1}{3} + i \frac{3}{3}

x = \frac{- 6 - 6 3 i}{2 \cdot 9} : - \frac{1}{3} - i \frac{3}{3}

The solutions to the quadratic equation are:

x = - \frac{1}{3} + i \frac{3}{3}, x = - \frac{1}{3} - i \frac{3}{3}

\frac{5 !}{1 ! \cdot ( 5 - 1 ) !}

- 19 = \frac{n}{8}

4 a + b - 12 a^{2} - 3 ab

x + 4 = 1

2 x^{8} y^{3} - 16 x^{5} y^{9}

What are the solutions to the equation 9x^2+6x+4=0 ?
The solutions to the equation 9x^2+6x+4=0 are x=-1/3+i(sqrt(3))/3 ,x=-1/3-i(sqrt(3))/3
Find the zeros of 9x^2+6x+4=0
The zeros of 9x^2+6x+4=0 are x=-1/3+i(sqrt(3))/3 ,x=-1/3-i(sqrt(3))/3