What are the solutions to the equation 4z^2+z+4=0 ?

The solutions to the equation 4z^2+z+4=0 are z=-1/8+i(3sqrt(7))/8 ,z=-1/8-i(3sqrt(7))/8

Find the zeros of 4z^2+z+4=0

The zeros of 4z^2+z+4=0 are z=-1/8+i(3sqrt(7))/8 ,z=-1/8-i(3sqrt(7))/8

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4 z^{2} + z + 4 = 0

z = - \frac{1}{8} + i \frac{3 7}{8}, z = - \frac{1}{8} - i \frac{3 7}{8}

Solution steps

4 z^{2} + z + 4 = 0

Solve with the quadratic formula

z_{1, 2} = \frac{- 1 \pm 1 ^{2} - 4 \cdot 4 \cdot 4}{2 \cdot 4}

Simplify

1^{2} - 4 \cdot 4 \cdot 4 : 37 i

z_{1, 2} = \frac{- 1 \pm 3 7 i}{2 \cdot 4}

Separate the solutions

z_{1} = \frac{- 1 + 3 7 i}{2 \cdot 4}, z_{2} = \frac{- 1 - 3 7 i}{2 \cdot 4}

z = \frac{- 1 + 3 7 i}{2 \cdot 4} : - \frac{1}{8} + i \frac{3 7}{8}

z = \frac{- 1 - 3 7 i}{2 \cdot 4} : - \frac{1}{8} - i \frac{3 7}{8}

The solutions to the quadratic equation are:

z = - \frac{1}{8} + i \frac{3 7}{8}, z = - \frac{1}{8} - i \frac{3 7}{8}

y + 4 = y - 4

\frac{4}{11} n = - \frac{16}{55}

- 2 + 2 x \geq (\frac{( x + 3 )}{2}) \geq - 10

\frac{x}{2} + 2 - \frac{x}{12} = \frac{x}{6} - \frac{5}{4}

3 (3 + 3)

What are the solutions to the equation 4z^2+z+4=0 ?
The solutions to the equation 4z^2+z+4=0 are z=-1/8+i(3sqrt(7))/8 ,z=-1/8-i(3sqrt(7))/8
Find the zeros of 4z^2+z+4=0
The zeros of 4z^2+z+4=0 are z=-1/8+i(3sqrt(7))/8 ,z=-1/8-i(3sqrt(7))/8