What are the solutions to the equation n^2+5n=0 ?

The solutions to the equation n^2+5n=0 are n=0,n=-5

Find the zeros of n^2+5n=0

The zeros of n^2+5n=0 are n=0,n=-5

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n^{2} + 5 n = 0

n = 0, n = - 5

Solution steps

n^{2} + 5 n = 0

Solve with the quadratic formula

n_{1, 2} = \frac{- 5 \pm 5 ^{2} - 4 \cdot 1 \cdot 0}{2 \cdot 1}

5^{2} - 4 \cdot 1 \cdot 0 = 5

n_{1, 2} = \frac{- 5 \pm 5}{2 \cdot 1}

Separate the solutions

n_{1} = \frac{- 5 + 5}{2 \cdot 1}, n_{2} = \frac{- 5 - 5}{2 \cdot 1}

n = \frac{- 5 + 5}{2 \cdot 1} : 0

n = \frac{- 5 - 5}{2 \cdot 1} : - 5

The solutions to the quadratic equation are:

n = 0, n = - 5

28 (x - 2) - 7 (x - 2)^{2}

∣ 3 - 2 y ∣ + 4 = 3

2 b a^{\frac{7}{4}} \cdot 3 a^{4} b^{\frac{1}{2}}

3 y + 6 + 4 y - 7 = - 8

2.2 < 11

What are the solutions to the equation n^2+5n=0 ?
The solutions to the equation n^2+5n=0 are n=0,n=-5
Find the zeros of n^2+5n=0
The zeros of n^2+5n=0 are n=0,n=-5