What are the solutions to the equation 9=12x-4x^2 ?

The solutions to the equation 9=12x-4x^2 are x= 3/2

Find the zeros of 9=12x-4x^2

The zeros of 9=12x-4x^2 are x= 3/2

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9 = 12 x - 4 x^{2}

x = \frac{3}{2}

Decimal Notation

x = 1.5

Solution steps

9 = 12 x - 4 x^{2}

Switch sides

12 x - 4 x^{2} = 9

Move

9

to the left side

12 x - 4 x^{2} - 9 = 0

Write in the standard form

a x^{2} + b x + c = 0

- 4 x^{2} + 12 x - 9 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 12 \pm 1 2 ^{2} - 4 ( - 4 ) ( - 9 )}{2 ( - 4 )}

1 2^{2} - 4 (- 4) (- 9) = 0

x_{1, 2} = \frac{- 12 \pm 0}{2 ( - 4 )}

x = \frac{- 12}{2 ( - 4 )}

\frac{- 12}{2 ( - 4 )} = \frac{3}{2}

x = \frac{3}{2}

The solution to the quadratic equation is:

x = \frac{3}{2}

4 x^{3} + 3 x^{2} + 28 x + 21

\frac{16}{25}

27 - x^{3}

\frac{3}{4} + \frac{1}{2}

x^{2} + 9 y^{2} + 6 x y

What are the solutions to the equation 9=12x-4x^2 ?
The solutions to the equation 9=12x-4x^2 are x= 3/2
Find the zeros of 9=12x-4x^2
The zeros of 9=12x-4x^2 are x= 3/2