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Popular >

|x+2|+6<= 11

Solution

∣ x + 2 ∣ + 6 \leq 11

Solution

- 7 \leq x \leq 3

+1

Solution steps

∣ x + 2 ∣ + 6 \leq 11

Move

6

to the right side

∣ x + 2 ∣ \leq 5

Apply absolute rule: If

∣ u ∣ \leq a, a > 0

then

- a \leq u \leq a

- 5 \leq x + 2 \leq 5

x + 2 \geq - 5 and x + 2 \leq 5

x \geq - 7 and x \leq 3

Merge Overlapping Intervals

- 7 \leq x \leq 3

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(\frac{5}{6}) (\frac{2}{3})

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12 x^{2} + 50 x + 50

- 8 x - 3 x = - 11 x

- 5 + 11 x - 2 x^{2} = 0

simplify log_{8}(16)simplify

lo g_{8} (16)

Frequently Asked Questions (FAQ)

What is |x+2|+6<= 11 ?
The solution to |x+2|+6<= 11 is -7<= x<= 3