What are the solutions to the equation 2k^2-14=-3k ?

The solutions to the equation 2k^2-14=-3k are k=2,k=-7/2

Find the zeros of 2k^2-14=-3k

The zeros of 2k^2-14=-3k are k=2,k=-7/2

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2 k^{2} - 14 = - 3 k

k = 2, k = - \frac{7}{2}

Solution steps

2 k^{2} - 14 = - 3 k

Move

3 k

to the left side

2 k^{2} - 14 + 3 k = 0

Write in the standard form

a x^{2} + b x + c = 0

2 k^{2} + 3 k - 14 = 0

Solve with the quadratic formula

k_{1, 2} = \frac{- 3 \pm 3 ^{2} - 4 \cdot 2 ( - 14 )}{2 \cdot 2}

3^{2} - 4 \cdot 2 (- 14) = 11

k_{1, 2} = \frac{- 3 \pm 11}{2 \cdot 2}

Separate the solutions

k_{1} = \frac{- 3 + 11}{2 \cdot 2}, k_{2} = \frac{- 3 - 11}{2 \cdot 2}

k = \frac{- 3 + 11}{2 \cdot 2} : 2

k = \frac{- 3 - 11}{2 \cdot 2} : - \frac{7}{2}

The solutions to the quadratic equation are:

k = 2, k = - \frac{7}{2}

2 x > 8

x^{2} + 2 x - 440 = 0

lo g_{16} (4) = x

- 1.18 = \frac{0.76}{0.5} (0) + b

(\frac{5}{3})^{2.2}

What are the solutions to the equation 2k^2-14=-3k ?
The solutions to the equation 2k^2-14=-3k are k=2,k=-7/2
Find the zeros of 2k^2-14=-3k
The zeros of 2k^2-14=-3k are k=2,k=-7/2