What are the solutions to the equation x^2+5x+7=0 ?

The solutions to the equation x^2+5x+7=0 are x=-5/2+i(sqrt(3))/2 ,x=-5/2-i(sqrt(3))/2

Find the zeros of x^2+5x+7=0

The zeros of x^2+5x+7=0 are x=-5/2+i(sqrt(3))/2 ,x=-5/2-i(sqrt(3))/2

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x^{2} + 5 x + 7 = 0

x = - \frac{5}{2} + i \frac{3}{2}, x = - \frac{5}{2} - i \frac{3}{2}

Solution steps

x^{2} + 5 x + 7 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 5 \pm 5 ^{2} - 4 \cdot 1 \cdot 7}{2 \cdot 1}

Simplify

5^{2} - 4 \cdot 1 \cdot 7 : 3 i

x_{1, 2} = \frac{- 5 \pm 3 i}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 5 + 3 i}{2 \cdot 1}, x_{2} = \frac{- 5 - 3 i}{2 \cdot 1}

x = \frac{- 5 + 3 i}{2 \cdot 1} : - \frac{5}{2} + i \frac{3}{2}

x = \frac{- 5 - 3 i}{2 \cdot 1} : - \frac{5}{2} - i \frac{3}{2}

The solutions to the quadratic equation are:

x = - \frac{5}{2} + i \frac{3}{2}, x = - \frac{5}{2} - i \frac{3}{2}

x^{8} - 29 x^{4} + 100

(\frac{2 ^{2} + 3 ^{2} + 3 ^{3}}{9})^{2} \cdot (\frac{1}{3})^{- 5}

26 = 2 π r

(2 - 3 i) (5 + i)

∣ 2 x + 1 ∣ \geq 1

What are the solutions to the equation x^2+5x+7=0 ?
The solutions to the equation x^2+5x+7=0 are x=-5/2+i(sqrt(3))/2 ,x=-5/2-i(sqrt(3))/2
Find the zeros of x^2+5x+7=0
The zeros of x^2+5x+7=0 are x=-5/2+i(sqrt(3))/2 ,x=-5/2-i(sqrt(3))/2