What are the solutions to the equation (x+1)(x-1)=0 ?

The solutions to the equation (x+1)(x-1)=0 are x=-1,x=1

Find the zeros of (x+1)(x-1)=0

The zeros of (x+1)(x-1)=0 are x=-1,x=1

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(x + 1) (x - 1) = 0

x = - 1, x = 1

Solution steps

(x + 1) (x - 1) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x + 1 = 0 or x - 1 = 0

Solve

x + 1 = 0 : x = - 1

Solve

x - 1 = 0 : x = 1

The solutions to the quadratic equation are:

x = - 1, x = 1

0.24 x + 0.42 = 1.74

18 \geq - x + 7

ln (6 x) \geq 4

2 (x + 7) < 3 (x + 4)

4 r^{2} - 144

What are the solutions to the equation (x+1)(x-1)=0 ?
The solutions to the equation (x+1)(x-1)=0 are x=-1,x=1
Find the zeros of (x+1)(x-1)=0
The zeros of (x+1)(x-1)=0 are x=-1,x=1