What are the solutions to the equation x^2+2x-36=0 ?

The solutions to the equation x^2+2x-36=0 are x=-1+sqrt(37),x=-1-sqrt(37)

Find the zeros of x^2+2x-36=0

The zeros of x^2+2x-36=0 are x=-1+sqrt(37),x=-1-sqrt(37)

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x^{2} + 2 x - 36 = 0

x = - 1 + 37, x = - 1 - 37

Solution steps

x^{2} + 2 x - 36 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 2 \pm 2 ^{2} - 4 \cdot 1 \cdot ( - 36 )}{2 \cdot 1}

2^{2} - 4 \cdot 1 \cdot (- 36) = 237

x_{1, 2} = \frac{- 2 \pm 2 37}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 2 + 2 37}{2 \cdot 1}, x_{2} = \frac{- 2 - 2 37}{2 \cdot 1}

x = \frac{- 2 + 2 37}{2 \cdot 1} : - 1 + 37

x = \frac{- 2 - 2 37}{2 \cdot 1} : - 1 - 37

The solutions to the quadratic equation are:

x = - 1 + 37, x = - 1 - 37

0 = 6 x^{2} + 78 x + 216

5 x + 3 \leq - 72 or 3 x + 1 > - 14

\frac{3}{2} ln (x - y) - 2 ln (x^{2} + y^{2})

\frac{9}{8} + \frac{8}{9}

What are the solutions to the equation x^2+2x-36=0 ?
The solutions to the equation x^2+2x-36=0 are x=-1+sqrt(37),x=-1-sqrt(37)
Find the zeros of x^2+2x-36=0
The zeros of x^2+2x-36=0 are x=-1+sqrt(37),x=-1-sqrt(37)