What are the solutions to the equation x^2+2x+4=9 ?

The solutions to the equation x^2+2x+4=9 are x=-1+sqrt(6),x=-1-sqrt(6)

Find the zeros of x^2+2x+4=9

The zeros of x^2+2x+4=9 are x=-1+sqrt(6),x=-1-sqrt(6)

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x^{2} + 2 x + 4 = 9

x = - 1 + 6, x = - 1 - 6

Solution steps

x^{2} + 2 x + 4 = 9

Move

9

to the left side

x^{2} + 2 x - 5 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 2 \pm 2 ^{2} - 4 \cdot 1 \cdot ( - 5 )}{2 \cdot 1}

2^{2} - 4 \cdot 1 \cdot (- 5) = 26

x_{1, 2} = \frac{- 2 \pm 2 6}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 2 + 2 6}{2 \cdot 1}, x_{2} = \frac{- 2 - 2 6}{2 \cdot 1}

x = \frac{- 2 + 2 6}{2 \cdot 1} : - 1 + 6

x = \frac{- 2 - 2 6}{2 \cdot 1} : - 1 - 6

The solutions to the quadratic equation are:

x = - 1 + 6, x = - 1 - 6

n + n^{2}

2 x - 4 = 11 - x

y^{2 + 2 x y}

- 2 i - (4 - i) 5 i

- 12 w^{2} + 20 w - 3 = 0

What are the solutions to the equation x^2+2x+4=9 ?
The solutions to the equation x^2+2x+4=9 are x=-1+sqrt(6),x=-1-sqrt(6)
Find the zeros of x^2+2x+4=9
The zeros of x^2+2x+4=9 are x=-1+sqrt(6),x=-1-sqrt(6)