What are the solutions to the equation 3x^2+13x=10 ?

The solutions to the equation 3x^2+13x=10 are x= 2/3 ,x=-5

Find the zeros of 3x^2+13x=10

The zeros of 3x^2+13x=10 are x= 2/3 ,x=-5

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3 x^{2} + 13 x = 10

x = \frac{2}{3}, x = - 5

Solution steps

3 x^{2} + 13 x = 10

Move

10

to the left side

3 x^{2} + 13 x - 10 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 13 \pm 1 3 ^{2} - 4 \cdot 3 ( - 10 )}{2 \cdot 3}

1 3^{2} - 4 \cdot 3 (- 10) = 17

x_{1, 2} = \frac{- 13 \pm 17}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- 13 + 17}{2 \cdot 3}, x_{2} = \frac{- 13 - 17}{2 \cdot 3}

x = \frac{- 13 + 17}{2 \cdot 3} : \frac{2}{3}

x = \frac{- 13 - 17}{2 \cdot 3} : - 5

The solutions to the quadratic equation are:

x = \frac{2}{3}, x = - 5

\frac{1}{7} x^{2} + \frac{1}{21} x - 1 = 0

\frac{7 π}{6} + 2 π

\frac{3}{4} \cdot \frac{2}{3}

12 m^{2} - 5 m

(\frac{7}{18})^{2}

What are the solutions to the equation 3x^2+13x=10 ?
The solutions to the equation 3x^2+13x=10 are x= 2/3 ,x=-5
Find the zeros of 3x^2+13x=10
The zeros of 3x^2+13x=10 are x= 2/3 ,x=-5