What are the solutions to the equation x^2-14x+42=0 ?

The solutions to the equation x^2-14x+42=0 are x=7+sqrt(7),x=7-sqrt(7)

Find the zeros of x^2-14x+42=0

The zeros of x^2-14x+42=0 are x=7+sqrt(7),x=7-sqrt(7)

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x^{2} - 14 x + 42 = 0

x = 7 + 7, x = 7 - 7

Decimal Notation

x = 9.64575 \dots, x = 4.35424 \dots

Solution steps

x^{2} - 14 x + 42 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 14 ) \pm ( - 14 ) ^{2} - 4 \cdot 1 \cdot 42}{2 \cdot 1}

(- 14)^{2} - 4 \cdot 1 \cdot 42 = 27

x_{1, 2} = \frac{- ( - 14 ) \pm 2 7}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 14 ) + 2 7}{2 \cdot 1}, x_{2} = \frac{- ( - 14 ) - 2 7}{2 \cdot 1}

x = \frac{- ( - 14 ) + 2 7}{2 \cdot 1} : 7 + 7

x = \frac{- ( - 14 ) - 2 7}{2 \cdot 1} : 7 - 7

The solutions to the quadratic equation are:

x = 7 + 7, x = 7 - 7

15 z + (4 - z) = 9 - (z - 6)

x - 2 < 2

\frac{2 ( 3 x + 7 )}{5} + \frac{5 ( x - 3 )}{2} = - 1

x^{2} - 9 x = - 8

88

What are the solutions to the equation x^2-14x+42=0 ?
The solutions to the equation x^2-14x+42=0 are x=7+sqrt(7),x=7-sqrt(7)
Find the zeros of x^2-14x+42=0
The zeros of x^2-14x+42=0 are x=7+sqrt(7),x=7-sqrt(7)