What are the solutions to the equation 2x^2-x-21=0 ?

The solutions to the equation 2x^2-x-21=0 are x= 7/2 ,x=-3

Find the zeros of 2x^2-x-21=0

The zeros of 2x^2-x-21=0 are x= 7/2 ,x=-3

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2 x^{2} - x - 21 = 0

x = \frac{7}{2}, x = - 3

Solution steps

2 x^{2} - x - 21 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 1 ) \pm ( - 1 ) ^{2} - 4 \cdot 2 ( - 21 )}{2 \cdot 2}

(- 1)^{2} - 4 \cdot 2 (- 21) = 13

x_{1, 2} = \frac{- ( - 1 ) \pm 13}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- ( - 1 ) + 13}{2 \cdot 2}, x_{2} = \frac{- ( - 1 ) - 13}{2 \cdot 2}

x = \frac{- ( - 1 ) + 13}{2 \cdot 2} : \frac{7}{2}

x = \frac{- ( - 1 ) - 13}{2 \cdot 2} : - 3

The solutions to the quadratic equation are:

x = \frac{7}{2}, x = - 3

u + \frac{4}{5} = - \frac{1}{2}

7 x^{2} - 15 x + 2

15 + x \geq 9

\frac{2 x}{3} + 4 = 3 x

12 - 23 + 108

What are the solutions to the equation 2x^2-x-21=0 ?
The solutions to the equation 2x^2-x-21=0 are x= 7/2 ,x=-3
Find the zeros of 2x^2-x-21=0
The zeros of 2x^2-x-21=0 are x= 7/2 ,x=-3