What are the solutions to the equation 9x^2-26x-3=0 ?

The solutions to the equation 9x^2-26x-3=0 are x=3,x=-1/9

Find the zeros of 9x^2-26x-3=0

The zeros of 9x^2-26x-3=0 are x=3,x=-1/9

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9 x^{2} - 26 x - 3 = 0

x = 3, x = - \frac{1}{9}

Decimal Notation

x = 3, x = - 0.11111 \dots

Solution steps

9 x^{2} - 26 x - 3 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 26 ) \pm ( - 26 ) ^{2} - 4 \cdot 9 ( - 3 )}{2 \cdot 9}

(- 26)^{2} - 4 \cdot 9 (- 3) = 28

x_{1, 2} = \frac{- ( - 26 ) \pm 28}{2 \cdot 9}

Separate the solutions

x_{1} = \frac{- ( - 26 ) + 28}{2 \cdot 9}, x_{2} = \frac{- ( - 26 ) - 28}{2 \cdot 9}

x = \frac{- ( - 26 ) + 28}{2 \cdot 9} : 3

x = \frac{- ( - 26 ) - 28}{2 \cdot 9} : - \frac{1}{9}

The solutions to the quadratic equation are:

x = 3, x = - \frac{1}{9}

(\frac{3}{4})^{2} - \frac{( \frac{1}{2} ) ^{3}}{\frac{3}{5}}

6 \cdot 9.81

\frac{1}{4 !}

\frac{2}{8} + \frac{2}{8}

i^{86}

What are the solutions to the equation 9x^2-26x-3=0 ?
The solutions to the equation 9x^2-26x-3=0 are x=3,x=-1/9
Find the zeros of 9x^2-26x-3=0
The zeros of 9x^2-26x-3=0 are x=3,x=-1/9