What are the solutions to the equation 6x^2+42x=0 ?

The solutions to the equation 6x^2+42x=0 are x=0,x=-7

Find the zeros of 6x^2+42x=0

The zeros of 6x^2+42x=0 are x=0,x=-7

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

6 x^{2} + 42 x = 0

x = 0, x = - 7

Solution steps

6 x^{2} + 42 x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 42 \pm 4 2 ^{2} - 4 \cdot 6 \cdot 0}{2 \cdot 6}

4 2^{2} - 4 \cdot 6 \cdot 0 = 42

x_{1, 2} = \frac{- 42 \pm 42}{2 \cdot 6}

Separate the solutions

x_{1} = \frac{- 42 + 42}{2 \cdot 6}, x_{2} = \frac{- 42 - 42}{2 \cdot 6}

x = \frac{- 42 + 42}{2 \cdot 6} : 0

x = \frac{- 42 - 42}{2 \cdot 6} : - 7

The solutions to the quadratic equation are:

x = 0, x = - 7

- 5 x + 4 (x - 2) < 0

- 4 x + 8 = 0

∣ x - 3 ∣ \geq 4

(x - 3)^{2} = 64

3 x - 1 > 17

What are the solutions to the equation 6x^2+42x=0 ?
The solutions to the equation 6x^2+42x=0 are x=0,x=-7
Find the zeros of 6x^2+42x=0
The zeros of 6x^2+42x=0 are x=0,x=-7