What are the solutions to the equation 0=-x^2+16 ?

The solutions to the equation 0=-x^2+16 are x=4,x=-4

Find the zeros of 0=-x^2+16

The zeros of 0=-x^2+16 are x=4,x=-4

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0 = - x^{2} + 16

x = 4, x = - 4

Solution steps

0 = - x^{2} + 16

Switch sides

- x^{2} + 16 = 0

Move

16

to the right side

- x^{2} = - 16

Divide both sides by

- 1

x^{2} = 16

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 16, x = - 16

16 = 4

- 16 = - 4

x = 4, x = - 4

x^{3} + 3 x^{2} - 10 x - 24

m - \frac{3}{- 2} \leq 5

2 x + 1 < - 1

t = - \frac{832}{2 ( - 16 )}

What are the solutions to the equation 0=-x^2+16 ?
The solutions to the equation 0=-x^2+16 are x=4,x=-4
Find the zeros of 0=-x^2+16
The zeros of 0=-x^2+16 are x=4,x=-4