What are the solutions to the equation x^2-11x+19=0 ?

The solutions to the equation x^2-11x+19=0 are x=(11+3sqrt(5))/2 ,x=(11-3sqrt(5))/2

Find the zeros of x^2-11x+19=0

The zeros of x^2-11x+19=0 are x=(11+3sqrt(5))/2 ,x=(11-3sqrt(5))/2

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x^{2} - 11 x + 19 = 0

x = \frac{11 + 3 5}{2}, x = \frac{11 - 3 5}{2}

Solution steps

x^{2} - 11 x + 19 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 11 ) \pm ( - 11 ) ^{2} - 4 \cdot 1 \cdot 19}{2 \cdot 1}

(- 11)^{2} - 4 \cdot 1 \cdot 19 = 35

x_{1, 2} = \frac{- ( - 11 ) \pm 3 5}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 11 ) + 3 5}{2 \cdot 1}, x_{2} = \frac{- ( - 11 ) - 3 5}{2 \cdot 1}

x = \frac{- ( - 11 ) + 3 5}{2 \cdot 1} : \frac{11 + 3 5}{2}

x = \frac{- ( - 11 ) - 3 5}{2 \cdot 1} : \frac{11 - 3 5}{2}

The solutions to the quadratic equation are:

x = \frac{11 + 3 5}{2}, x = \frac{11 - 3 5}{2}

(5 \cdot 2 \cdot 3)^{4}

∣ 5 x ∣ > 15

2 x - x^{2} = - x

(x + 2) (x + 2) = 1

\frac{x}{6} = 7

What are the solutions to the equation x^2-11x+19=0 ?
The solutions to the equation x^2-11x+19=0 are x=(11+3sqrt(5))/2 ,x=(11-3sqrt(5))/2
Find the zeros of x^2-11x+19=0
The zeros of x^2-11x+19=0 are x=(11+3sqrt(5))/2 ,x=(11-3sqrt(5))/2