What are the solutions to the equation 2x^2-9x-2=0 ?

The solutions to the equation 2x^2-9x-2=0 are x=(9+sqrt(97))/4 ,x=(9-sqrt(97))/4

Find the zeros of 2x^2-9x-2=0

The zeros of 2x^2-9x-2=0 are x=(9+sqrt(97))/4 ,x=(9-sqrt(97))/4

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2 x^{2} - 9 x - 2 = 0

x = \frac{9 + 97}{4}, x = \frac{9 - 97}{4}

Solution steps

2 x^{2} - 9 x - 2 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 9 ) \pm ( - 9 ) ^{2} - 4 \cdot 2 ( - 2 )}{2 \cdot 2}

(- 9)^{2} - 4 \cdot 2 (- 2) = 97

x_{1, 2} = \frac{- ( - 9 ) \pm 97}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- ( - 9 ) + 97}{2 \cdot 2}, x_{2} = \frac{- ( - 9 ) - 97}{2 \cdot 2}

x = \frac{- ( - 9 ) + 97}{2 \cdot 2} : \frac{9 + 97}{4}

x = \frac{- ( - 9 ) - 97}{2 \cdot 2} : \frac{9 - 97}{4}

The solutions to the quadratic equation are:

x = \frac{9 + 97}{4}, x = \frac{9 - 97}{4}

4 (3 x - 1) = - 6 + 2 (6 x + 1)

5 x^{2} = 80

\frac{4.0 1 ^{2} - 16}{4.01 - 4}

2 (2 x - 2) + 3 x + 12 = 5 x + 10

4 - y = 32

What are the solutions to the equation 2x^2-9x-2=0 ?
The solutions to the equation 2x^2-9x-2=0 are x=(9+sqrt(97))/4 ,x=(9-sqrt(97))/4
Find the zeros of 2x^2-9x-2=0
The zeros of 2x^2-9x-2=0 are x=(9+sqrt(97))/4 ,x=(9-sqrt(97))/4