What are the solutions to the equation 0=x^2+2x+4 ?

The solutions to the equation 0=x^2+2x+4 are x=-1+sqrt(3)i,x=-1-sqrt(3)i

Find the zeros of 0=x^2+2x+4

The zeros of 0=x^2+2x+4 are x=-1+sqrt(3)i,x=-1-sqrt(3)i

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0 = x^{2} + 2 x + 4

x = - 1 + 3 i, x = - 1 - 3 i

Solution steps

0 = x^{2} + 2 x + 4

Switch sides

x^{2} + 2 x + 4 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 2 \pm 2 ^{2} - 4 \cdot 1 \cdot 4}{2 \cdot 1}

Simplify

2^{2} - 4 \cdot 1 \cdot 4 : 23 i

x_{1, 2} = \frac{- 2 \pm 2 3 i}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 2 + 2 3 i}{2 \cdot 1}, x_{2} = \frac{- 2 - 2 3 i}{2 \cdot 1}

x = \frac{- 2 + 2 3 i}{2 \cdot 1} : - 1 + 3 i

x = \frac{- 2 - 2 3 i}{2 \cdot 1} : - 1 - 3 i

The solutions to the quadratic equation are:

x = - 1 + 3 i, x = - 1 - 3 i

x^{2} + 7.5 x - 38.5 > 0

40 + 210 + 90

2 x - 5 = - x + 19

- 2 \leq \frac{\frac{1}{x + 4} - \frac{1}{4}}{x} \leq x

m^{4} + m^{3} + m^{2} + m

What are the solutions to the equation 0=x^2+2x+4 ?
The solutions to the equation 0=x^2+2x+4 are x=-1+sqrt(3)i,x=-1-sqrt(3)i
Find the zeros of 0=x^2+2x+4
The zeros of 0=x^2+2x+4 are x=-1+sqrt(3)i,x=-1-sqrt(3)i