What are the solutions to the equation 2(x+3/4)^2-5=123 ?

The solutions to the equation 2(x+3/4)^2-5=123 are x= 29/4 ,x=-35/4

Find the zeros of 2(x+3/4)^2-5=123

The zeros of 2(x+3/4)^2-5=123 are x= 29/4 ,x=-35/4

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2 (x + \frac{3}{4})^{2} - 5 = 123

x = \frac{29}{4}, x = - \frac{35}{4}

Decimal Notation

x = 7.25, x = - 8.75

Solution steps

2 (x + \frac{3}{4})^{2} - 5 = 123

Move

5

to the right side

2 (x + \frac{3}{4})^{2} = 128

Divide both sides by

2

(x + \frac{3}{4})^{2} = 64

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x + \frac{3}{4} = 64 : x = \frac{29}{4}

Solve

x + \frac{3}{4} = - 64 : x = - \frac{35}{4}

The solutions to the quadratic equation are:

x = \frac{29}{4}, x = - \frac{35}{4}

\frac{4}{3} x - \frac{2}{5} = \frac{7}{5} x - \frac{1}{10}

14 y^{2} = 1 - 5 y

4^{- 5}

x + 5 + 6 x^{- 1}

a^{4} + 5 a^{2} - 36

What are the solutions to the equation 2(x+3/4)^2-5=123 ?
The solutions to the equation 2(x+3/4)^2-5=123 are x= 29/4 ,x=-35/4
Find the zeros of 2(x+3/4)^2-5=123
The zeros of 2(x+3/4)^2-5=123 are x= 29/4 ,x=-35/4