What are the solutions to the equation 7x^2-5x=0 ?

The solutions to the equation 7x^2-5x=0 are x= 5/7 ,x=0

Find the zeros of 7x^2-5x=0

The zeros of 7x^2-5x=0 are x= 5/7 ,x=0

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7 x^{2} - 5 x = 0

x = \frac{5}{7}, x = 0

Decimal Notation

x = 0.71428 \dots, x = 0

Solution steps

7 x^{2} - 5 x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 5 ) \pm ( - 5 ) ^{2} - 4 \cdot 7 \cdot 0}{2 \cdot 7}

(- 5)^{2} - 4 \cdot 7 \cdot 0 = 5

x_{1, 2} = \frac{- ( - 5 ) \pm 5}{2 \cdot 7}

Separate the solutions

x_{1} = \frac{- ( - 5 ) + 5}{2 \cdot 7}, x_{2} = \frac{- ( - 5 ) - 5}{2 \cdot 7}

x = \frac{- ( - 5 ) + 5}{2 \cdot 7} : \frac{5}{7}

x = \frac{- ( - 5 ) - 5}{2 \cdot 7} : 0

The solutions to the quadratic equation are:

x = \frac{5}{7}, x = 0

(x - 5)^{2} = 16

- 63 = - 7 c

\frac{- 3 x + 1}{3} + \frac{5}{3} = - \frac{5 x}{4}

161

\frac{e ^{2}}{e ^{3}}

What are the solutions to the equation 7x^2-5x=0 ?
The solutions to the equation 7x^2-5x=0 are x= 5/7 ,x=0
Find the zeros of 7x^2-5x=0
The zeros of 7x^2-5x=0 are x= 5/7 ,x=0