What is (x+7)(1/2 x^{-1/2}) ?

The solution to (x+7)(1/2 x^{-1/2}) is (x+7)/(2x^{1/2)}

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simplify (x+7)(1/2 x^{-1/2})

simplify

(x + 7) (\frac{1}{2} x^{- \frac{1}{2}})

\frac{x + 7}{2 x ^{\frac{1}{2}}}

Solution steps

(x + 7) (\frac{1}{2} x^{- \frac{1}{2}})

Simplify

\frac{1}{2} x^{- \frac{1}{2}} : \frac{1}{2 x ^{\frac{1}{2}}}

= (x + 7) \frac{1}{2 x ^{\frac{1}{2}}}

Apply the fraction rule:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{( x + 7 ) \cdot 1}{2 x ^{\frac{1}{2}}}

Apply rule:

a \cdot 1 = a

(x + 7) \cdot 1 = (x + 7)

= \frac{x + 7}{2 x ^{\frac{1}{2}}}

2 \cdot 14

lo g_{4} (0.5)

5 x^{2} = 7

2 x^{3} + 8 x^{2} + 3 x + 12

3 x^{2} - 24 x + 36 < 0

What is (x+7)(1/2 x^{-1/2}) ?
The solution to (x+7)(1/2 x^{-1/2}) is (x+7)/(2x^{1/2)}