What is |x+1|>= 7-2x ?

The solution to |x+1|>= 7-2x is x>= 2

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|x+1|>= 7-2x

∣ x + 1 ∣ \geq 7 - 2 x

x \geq 2

Solution steps

∣ x + 1 ∣ \geq 7 - 2 x

Find positive and negative intervals

x < - 1, x \geq - 1

Solve the inequality for each interval

No Solution or x \geq 2

Merge Overlapping Intervals

x \geq 2

\frac{x ^{2} + 5 x - 6}{x ^{2} - 8 x + 16} \geq 0

6 x + 1 \leq 4 x - 9

\frac{1}{4} (8 - 16 x) \leq - 6

x + 6 = 2

lo g_{2} (x) < 3