What is the answer to (x+1)^3+(x-1)^3=2x^3 ?

The answer to (x+1)^3+(x-1)^3=2x^3 is x=0

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(x+1)^3+(x-1)^3=2x^3

(x + 1)^{3} + (x - 1)^{3} = 2 x^{3}

x = 0

Solution steps

(x + 1)^{3} + (x - 1)^{3} = 2 x^{3}

Expand

(x + 1)^{3} + (x - 1)^{3} : 2 x^{3} + 6 x

2 x^{3} + 6 x = 2 x^{3}

Move

2 x^{3}

to the left side

6 x = 0

Divide both sides by

6

x = 0

\frac{2}{3} t = 9

∣ 2 x - 19 ∣ < 5

\frac{1}{2} x - 2 < 3 x - \frac{3}{2}

(8 x + 5) 2 + (8 x + 5) (4 x - 3)

3 x^{2} - 14 x + 15

What is the answer to (x+1)^3+(x-1)^3=2x^3 ?
The answer to (x+1)^3+(x-1)^3=2x^3 is x=0
Solve for x: (x+1)^3+(x-1)^3=2x^3
The solution is x=0