What are the solutions to the equation x^2+6x-11=0 ?

The solutions to the equation x^2+6x-11=0 are x=-3+2sqrt(5),x=-3-2sqrt(5)

Find the zeros of x^2+6x-11=0

The zeros of x^2+6x-11=0 are x=-3+2sqrt(5),x=-3-2sqrt(5)

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x^{2} + 6 x - 11 = 0

x = - 3 + 25, x = - 3 - 25

Solution steps

x^{2} + 6 x - 11 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 6 \pm 6 ^{2} - 4 \cdot 1 \cdot ( - 11 )}{2 \cdot 1}

6^{2} - 4 \cdot 1 \cdot (- 11) = 45

x_{1, 2} = \frac{- 6 \pm 4 5}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 6 + 4 5}{2 \cdot 1}, x_{2} = \frac{- 6 - 4 5}{2 \cdot 1}

x = \frac{- 6 + 4 5}{2 \cdot 1} : - 3 + 25

x = \frac{- 6 - 4 5}{2 \cdot 1} : - 3 - 25

The solutions to the quadratic equation are:

x = - 3 + 25, x = - 3 - 25

\frac{h}{3} + \frac{h}{6} = 1

3 x^{3} + 4 x^{2} - 7 x + 2

\frac{x + 3}{8 x} = 77

x - 3 \cdot \frac{2 x + 1}{2} = - 3 (- \frac{3 x + 9}{3} - 2 + x) - \frac{x}{2}

(4 x^{3} y)^{2}

What are the solutions to the equation x^2+6x-11=0 ?
The solutions to the equation x^2+6x-11=0 are x=-3+2sqrt(5),x=-3-2sqrt(5)
Find the zeros of x^2+6x-11=0
The zeros of x^2+6x-11=0 are x=-3+2sqrt(5),x=-3-2sqrt(5)