What are the solutions to the equation 192x^2-16=0 ?

The solutions to the equation 192x^2-16=0 are x= 1/(2sqrt(3)),x=-1/(2sqrt(3))

Find the zeros of 192x^2-16=0

The zeros of 192x^2-16=0 are x= 1/(2sqrt(3)),x=-1/(2sqrt(3))

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192 x^{2} - 16 = 0

x = \frac{1}{2 3}, x = - \frac{1}{2 3}

Decimal Notation

x = 0.28867 \dots, x = - 0.28867 \dots

Solution steps

192 x^{2} - 16 = 0

Move

16

to the right side

192 x^{2} = 16

Divide both sides by

192

x^{2} = \frac{1}{12}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = \frac{1}{12}, x = - \frac{1}{12}

\frac{1}{12} = \frac{1}{2 3}

- \frac{1}{12} = - \frac{1}{2 3}

x = \frac{1}{2 3}, x = - \frac{1}{2 3}

\frac{2 π}{\frac{3 π}{4}}

\frac{5}{6} \cdot 5

- - 5

- 4 x = x^{2}

1 - \frac{5}{2} x \leq 16

What are the solutions to the equation 192x^2-16=0 ?
The solutions to the equation 192x^2-16=0 are x= 1/(2sqrt(3)),x=-1/(2sqrt(3))
Find the zeros of 192x^2-16=0
The zeros of 192x^2-16=0 are x= 1/(2sqrt(3)),x=-1/(2sqrt(3))