What is (m^{-2}n^{-5})/((m^4n^3)^{-1)} ?

The solution to (m^{-2}n^{-5})/((m^4n^3)^{-1)} is (m^2)/(n^2)

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simplify (m^{-2}n^{-5})/((m^4n^3)^{-1)}

simplify

\frac{m ^{- 2} n ^{- 5}}{( m ^{4} n ^{3} ) ^{- 1}}

\frac{m ^{2}}{n ^{2}}

Solution steps

\frac{m ^{- 2} n ^{- 5}}{( m ^{4} n ^{3} ) ^{- 1}}

Simplify

m^{- 2} n^{- 5} : \frac{1}{m ^{2} n ^{5}}

= \frac{\frac{1}{m ^{2} n ^{5}}}{( m ^{4} n ^{3} ) ^{- 1}}

Apply the fraction rule:

\frac{\frac{a}{b}}{c} = \frac{a}{b \cdot c}

= \frac{1}{m ^{2} n ^{5} ( m ^{4} n ^{3} ) ^{- 1}}

Simplify

m^{2} n^{5} (m^{4} n^{3})^{- 1} : \frac{n ^{2}}{m ^{2}}

= \frac{1}{\frac{n ^{2}}{m ^{2}}}

Apply the fraction rule:

\frac{1}{\frac{b}{c}} = \frac{c}{b}

= \frac{m ^{2}}{n ^{2}}

\frac{1 - \frac{s}{t}}{1 + \frac{s}{t}}

∣ 2 x - 1 ∣ > ∣ x + 2 ∣

x^{2} > 4

- x^{2} + 6 x - 9

What is (m^{-2}n^{-5})/((m^4n^3)^{-1)} ?
The solution to (m^{-2}n^{-5})/((m^4n^3)^{-1)} is (m^2)/(n^2)