What are the solutions to the equation -3x^2-24x+17=-40 ?

The solutions to the equation -3x^2-24x+17=-40 are x=-4-sqrt(35),x=sqrt(35)-4

Find the zeros of -3x^2-24x+17=-40

The zeros of -3x^2-24x+17=-40 are x=-4-sqrt(35),x=sqrt(35)-4

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- 3 x^{2} - 24 x + 17 = - 40

x = - 4 - 35, x = 35 - 4

Solution steps

- 3 x^{2} - 24 x + 17 = - 40

Move

40

to the left side

- 3 x^{2} - 24 x + 57 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 24 ) \pm ( - 24 ) ^{2} - 4 ( - 3 ) \cdot 57}{2 ( - 3 )}

(- 24)^{2} - 4 (- 3) \cdot 57 = 635

x_{1, 2} = \frac{- ( - 24 ) \pm 6 35}{2 ( - 3 )}

Separate the solutions

x_{1} = \frac{- ( - 24 ) + 6 35}{2 ( - 3 )}, x_{2} = \frac{- ( - 24 ) - 6 35}{2 ( - 3 )}

x = \frac{- ( - 24 ) + 6 35}{2 ( - 3 )} : - 4 - 35

x = \frac{- ( - 24 ) - 6 35}{2 ( - 3 )} : 35 - 4

The solutions to the quadratic equation are:

x = - 4 - 35, x = 35 - 4

x^{2} - 10 x + 26 = 0

(- 2 + 4 i) - (- 4 + 4 i)

\frac{5}{2} (2)^{1}

26 \cdot 2

(x - 5)^{2} = 12

What are the solutions to the equation -3x^2-24x+17=-40 ?
The solutions to the equation -3x^2-24x+17=-40 are x=-4-sqrt(35),x=sqrt(35)-4
Find the zeros of -3x^2-24x+17=-40
The zeros of -3x^2-24x+17=-40 are x=-4-sqrt(35),x=sqrt(35)-4