What are the solutions to the equation x^2+8x=240 ?

The solutions to the equation x^2+8x=240 are x=12,x=-20

Find the zeros of x^2+8x=240

The zeros of x^2+8x=240 are x=12,x=-20

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x^{2} + 8 x = 240

x = 12, x = - 20

Solution steps

x^{2} + 8 x = 240

Move

240

to the left side

x^{2} + 8 x - 240 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 8 \pm 8 ^{2} - 4 \cdot 1 \cdot ( - 240 )}{2 \cdot 1}

8^{2} - 4 \cdot 1 \cdot (- 240) = 32

x_{1, 2} = \frac{- 8 \pm 32}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 8 + 32}{2 \cdot 1}, x_{2} = \frac{- 8 - 32}{2 \cdot 1}

x = \frac{- 8 + 32}{2 \cdot 1} : 12

x = \frac{- 8 - 32}{2 \cdot 1} : - 20

The solutions to the quadratic equation are:

x = 12, x = - 20

- 5 k + 10 = - 2 k - 14

- 4 x - 19 = x^{2}

x - (7 x - 3) \leq 7 - 2 (1 - 2 x)

2 x + 1 \geq 5

9 (x - 2) \leq - 3 (x - 6)

What are the solutions to the equation x^2+8x=240 ?
The solutions to the equation x^2+8x=240 are x=12,x=-20
Find the zeros of x^2+8x=240
The zeros of x^2+8x=240 are x=12,x=-20