What are the solutions to the equation (2x+8)(x-5)=0 ?

The solutions to the equation (2x+8)(x-5)=0 are x=-4,x=5

Find the zeros of (2x+8)(x-5)=0

The zeros of (2x+8)(x-5)=0 are x=-4,x=5

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(2 x + 8) (x - 5) = 0

x = - 4, x = 5

Solution steps

(2 x + 8) (x - 5) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

2 x + 8 = 0 or x - 5 = 0

Solve

2 x + 8 = 0 : x = - 4

Solve

x - 5 = 0 : x = 5

The solutions to the quadratic equation are:

x = - 4, x = 5

∣ 2 x - 1 ∣ = 6

4 (3 x - 6) = 24

32 x^{2} y - 2 y

x y + 5 y - 8 x - 40

(\frac{64}{125})^{- \frac{4}{3}}

What are the solutions to the equation (2x+8)(x-5)=0 ?
The solutions to the equation (2x+8)(x-5)=0 are x=-4,x=5
Find the zeros of (2x+8)(x-5)=0
The zeros of (2x+8)(x-5)=0 are x=-4,x=5