What are the solutions to the equation x^2-39=-10x ?

The solutions to the equation x^2-39=-10x are x=3,x=-13

Find the zeros of x^2-39=-10x

The zeros of x^2-39=-10x are x=3,x=-13

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x^{2} - 39 = - 10 x

x = 3, x = - 13

Solution steps

x^{2} - 39 = - 10 x

Move

10 x

to the left side

x^{2} - 39 + 10 x = 0

Write in the standard form

a x^{2} + b x + c = 0

x^{2} + 10 x - 39 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 10 \pm 1 0 ^{2} - 4 \cdot 1 \cdot ( - 39 )}{2 \cdot 1}

1 0^{2} - 4 \cdot 1 \cdot (- 39) = 16

x_{1, 2} = \frac{- 10 \pm 16}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 10 + 16}{2 \cdot 1}, x_{2} = \frac{- 10 - 16}{2 \cdot 1}

x = \frac{- 10 + 16}{2 \cdot 1} : 3

x = \frac{- 10 - 16}{2 \cdot 1} : - 13

The solutions to the quadratic equation are:

x = 3, x = - 13

\frac{2 ( x + 3 )}{- 5} \leq - x

\frac{x y - 3 y + x - 3}{x y + 2 y - x - 2}

\frac{500000}{x ^{2} + 400} < 400

180 = 22 + (x - 5)

2 x^{3} + 4 x^{2} - 30 x

What are the solutions to the equation x^2-39=-10x ?
The solutions to the equation x^2-39=-10x are x=3,x=-13
Find the zeros of x^2-39=-10x
The zeros of x^2-39=-10x are x=3,x=-13