What is (k^2-8k+16)/(k^2-16) ?

The solution to (k^2-8k+16)/(k^2-16) is (k-4)/(k+4)

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simplify (k^2-8k+16)/(k^2-16)

simplify

\frac{k ^{2} - 8 k + 16}{k ^{2} - 16}

\frac{k - 4}{k + 4}

Solution steps

\frac{k ^{2} - 8 k + 16}{k ^{2} - 16}

Factor

k^{2} - 8 k + 16 : (k - 4)^{2}

= \frac{( k - 4 ) ^{2}}{k ^{2} - 16}

Factor

k^{2} - 16 : (k + 4) (k - 4)

= \frac{( k - 4 ) ^{2}}{( k + 4 ) ( k - 4 )}

Apply exponent rule:

a^{b + c} = a^{b} \cdot a^{c}

(k - 4)^{2} = (k - 4) (k - 4)

= \frac{( k - 4 ) ( k - 4 )}{( k + 4 ) ( k - 4 )}

Cancel the common factor:

k - 4

= \frac{k - 4}{k + 4}

10 a^{2} + 101 ab + 10 b^{2}

8 \cdot 1 0^{3}

\frac{149 π}{180} - \frac{5 π}{6}

3 x^{2} \cdot x

x^{2} < 64

What is (k^2-8k+16)/(k^2-16) ?
The solution to (k^2-8k+16)/(k^2-16) is (k-4)/(k+4)