What are the solutions to the equation 25x^2+35x=5x-17 ?

The solutions to the equation 25x^2+35x=5x-17 are x=-3/5+i(2sqrt(2))/5 ,x=-3/5-i(2sqrt(2))/5

Find the zeros of 25x^2+35x=5x-17

The zeros of 25x^2+35x=5x-17 are x=-3/5+i(2sqrt(2))/5 ,x=-3/5-i(2sqrt(2))/5

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25 x^{2} + 35 x = 5 x - 17

x = - \frac{3}{5} + i \frac{2 2}{5}, x = - \frac{3}{5} - i \frac{2 2}{5}

Solution steps

25 x^{2} + 35 x = 5 x - 17

Move

17

to the left side

25 x^{2} + 35 x + 17 = 5 x

Move

5 x

to the left side

25 x^{2} + 30 x + 17 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 30 \pm 3 0 ^{2} - 4 \cdot 25 \cdot 17}{2 \cdot 25}

Simplify

3 0^{2} - 4 \cdot 25 \cdot 17 : 202 i

x_{1, 2} = \frac{- 30 \pm 20 2 i}{2 \cdot 25}

Separate the solutions

x_{1} = \frac{- 30 + 20 2 i}{2 \cdot 25}, x_{2} = \frac{- 30 - 20 2 i}{2 \cdot 25}

x = \frac{- 30 + 20 2 i}{2 \cdot 25} : - \frac{3}{5} + i \frac{2 2}{5}

x = \frac{- 30 - 20 2 i}{2 \cdot 25} : - \frac{3}{5} - i \frac{2 2}{5}

The solutions to the quadratic equation are:

x = - \frac{3}{5} + i \frac{2 2}{5}, x = - \frac{3}{5} - i \frac{2 2}{5}

6 - (- 4)

- 3 t^{2} + 30 t - 72 = 0

\frac{x}{x + 2} - \frac{5}{x - 4} < 0

5 x^{2} - 9 x = 2

x^{2} - 9 x < 0

What are the solutions to the equation 25x^2+35x=5x-17 ?
The solutions to the equation 25x^2+35x=5x-17 are x=-3/5+i(2sqrt(2))/5 ,x=-3/5-i(2sqrt(2))/5
Find the zeros of 25x^2+35x=5x-17
The zeros of 25x^2+35x=5x-17 are x=-3/5+i(2sqrt(2))/5 ,x=-3/5-i(2sqrt(2))/5