What are the solutions to the equation 30=x^2+x ?

The solutions to the equation 30=x^2+x are x=5,x=-6

Find the zeros of 30=x^2+x

The zeros of 30=x^2+x are x=5,x=-6

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30 = x^{2} + x

x = 5, x = - 6

Solution steps

30 = x^{2} + x

Switch sides

x^{2} + x = 30

Move

30

to the left side

x^{2} + x - 30 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 1 \pm 1 ^{2} - 4 \cdot 1 \cdot ( - 30 )}{2 \cdot 1}

1^{2} - 4 \cdot 1 \cdot (- 30) = 11

x_{1, 2} = \frac{- 1 \pm 11}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 1 + 11}{2 \cdot 1}, x_{2} = \frac{- 1 - 11}{2 \cdot 1}

x = \frac{- 1 + 11}{2 \cdot 1} : 5

x = \frac{- 1 - 11}{2 \cdot 1} : - 6

The solutions to the quadratic equation are:

x = 5, x = - 6

2 x^{2} + 3 x > - 1

\frac{2 ∣ x - 1 ∣}{5} \geq 2

- 3 x^{2} = 0

6 x^{2} + 5 x - 4

\frac{15 a ^{8} b ^{3}}{45 a ^{7} b}

What are the solutions to the equation 30=x^2+x ?
The solutions to the equation 30=x^2+x are x=5,x=-6
Find the zeros of 30=x^2+x
The zeros of 30=x^2+x are x=5,x=-6