What are the solutions to the equation -x^2+6x=x^2-4x ?

The solutions to the equation -x^2+6x=x^2-4x are x=0,x=5

Find the zeros of -x^2+6x=x^2-4x

The zeros of -x^2+6x=x^2-4x are x=0,x=5

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- x^{2} + 6 x = x^{2} - 4 x

x = 0, x = 5

Solution steps

- x^{2} + 6 x = x^{2} - 4 x

Move

4 x

to the left side

- x^{2} + 10 x = x^{2}

Move

x^{2}

to the left side

- 2 x^{2} + 10 x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 10 \pm 1 0 ^{2} - 4 ( - 2 ) \cdot 0}{2 ( - 2 )}

1 0^{2} - 4 (- 2) \cdot 0 = 10

x_{1, 2} = \frac{- 10 \pm 10}{2 ( - 2 )}

Separate the solutions

x_{1} = \frac{- 10 + 10}{2 ( - 2 )}, x_{2} = \frac{- 10 - 10}{2 ( - 2 )}

x = \frac{- 10 + 10}{2 ( - 2 )} : 0

x = \frac{- 10 - 10}{2 ( - 2 )} : 5

The solutions to the quadratic equation are:

x = 0, x = 5

- 1 - a \leq 1

3 s^{2} - 16 s + 5

mn + 7 n - m - 7

6 x^{2} = - 300

z^{2} - 6 z + 9

What are the solutions to the equation -x^2+6x=x^2-4x ?
The solutions to the equation -x^2+6x=x^2-4x are x=0,x=5
Find the zeros of -x^2+6x=x^2-4x
The zeros of -x^2+6x=x^2-4x are x=0,x=5