What are the solutions to the equation 64w^2+96w+36=0 ?

The solutions to the equation 64w^2+96w+36=0 are w=-3/4

Find the zeros of 64w^2+96w+36=0

The zeros of 64w^2+96w+36=0 are w=-3/4

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64 w^{2} + 96 w + 36 = 0

w = - \frac{3}{4}

Solution steps

64 w^{2} + 96 w + 36 = 0

Solve with the quadratic formula

w_{1, 2} = \frac{- 96 \pm 9 6 ^{2} - 4 \cdot 64 \cdot 36}{2 \cdot 64}

9 6^{2} - 4 \cdot 64 \cdot 36 = 0

w_{1, 2} = \frac{- 96 \pm 0}{2 \cdot 64}

w = \frac{- 96}{2 \cdot 64}

\frac{- 96}{2 \cdot 64} = - \frac{3}{4}

w = - \frac{3}{4}

The solution to the quadratic equation is:

w = - \frac{3}{4}

\frac{a ^{- 4} b ^{4}}{4 a ^{0} b ^{- 4}}

0.01 = (0.000001) (64) (256 - x)

- \frac{70}{3} + 10

26 + 324

5 - 3

What are the solutions to the equation 64w^2+96w+36=0 ?
The solutions to the equation 64w^2+96w+36=0 are w=-3/4
Find the zeros of 64w^2+96w+36=0
The zeros of 64w^2+96w+36=0 are w=-3/4