What are the solutions to the equation x^2-9x-36=0 ?

The solutions to the equation x^2-9x-36=0 are x=12,x=-3

Find the zeros of x^2-9x-36=0

The zeros of x^2-9x-36=0 are x=12,x=-3

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x^{2} - 9 x - 36 = 0

x = 12, x = - 3

Solution steps

x^{2} - 9 x - 36 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 9 ) \pm ( - 9 ) ^{2} - 4 \cdot 1 \cdot ( - 36 )}{2 \cdot 1}

(- 9)^{2} - 4 \cdot 1 \cdot (- 36) = 15

x_{1, 2} = \frac{- ( - 9 ) \pm 15}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 9 ) + 15}{2 \cdot 1}, x_{2} = \frac{- ( - 9 ) - 15}{2 \cdot 1}

x = \frac{- ( - 9 ) + 15}{2 \cdot 1} : 12

x = \frac{- ( - 9 ) - 15}{2 \cdot 1} : - 3

The solutions to the quadratic equation are:

x = 12, x = - 3

\frac{x - 1}{x + 2} \leq 2

(x + 2) - 1 = 7 - 2 x

3 y^{2} + 19 y + 6 = 0

- 4 n + 3 > - 5

8 m - 20 n

What are the solutions to the equation x^2-9x-36=0 ?
The solutions to the equation x^2-9x-36=0 are x=12,x=-3
Find the zeros of x^2-9x-36=0
The zeros of x^2-9x-36=0 are x=12,x=-3