What are the solutions to the equation 7k^2-16k+100=0 ?

The solutions to the equation 7k^2-16k+100=0 are k= 8/7+i(2sqrt(159))/7 ,k= 8/7-i(2sqrt(159))/7

Find the zeros of 7k^2-16k+100=0

The zeros of 7k^2-16k+100=0 are k= 8/7+i(2sqrt(159))/7 ,k= 8/7-i(2sqrt(159))/7

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

7 k^{2} - 16 k + 100 = 0

k = \frac{8}{7} + i \frac{2 159}{7}, k = \frac{8}{7} - i \frac{2 159}{7}

Solution steps

7 k^{2} - 16 k + 100 = 0

Solve with the quadratic formula

k_{1, 2} = \frac{- ( - 16 ) \pm ( - 16 ) ^{2} - 4 \cdot 7 \cdot 100}{2 \cdot 7}

Simplify

(- 16)^{2} - 4 \cdot 7 \cdot 100 : 4159 i

k_{1, 2} = \frac{- ( - 16 ) \pm 4 159 i}{2 \cdot 7}

Separate the solutions

k_{1} = \frac{- ( - 16 ) + 4 159 i}{2 \cdot 7}, k_{2} = \frac{- ( - 16 ) - 4 159 i}{2 \cdot 7}

k = \frac{- ( - 16 ) + 4 159 i}{2 \cdot 7} : \frac{8}{7} + i \frac{2 159}{7}

k = \frac{- ( - 16 ) - 4 159 i}{2 \cdot 7} : \frac{8}{7} - i \frac{2 159}{7}

The solutions to the quadratic equation are:

k = \frac{8}{7} + i \frac{2 159}{7}, k = \frac{8}{7} - i \frac{2 159}{7}

9 x^{3} - 4 x

\frac{1 0 ^{0}}{1 0 ^{5}}

0 = x^{2} + x - 12

7 (x + 2) + 5 \geq - 3 x - 3

\frac{9}{8} m - \frac{1}{6} m = - 4 - \frac{11}{3}

What are the solutions to the equation 7k^2-16k+100=0 ?
The solutions to the equation 7k^2-16k+100=0 are k= 8/7+i(2sqrt(159))/7 ,k= 8/7-i(2sqrt(159))/7
Find the zeros of 7k^2-16k+100=0
The zeros of 7k^2-16k+100=0 are k= 8/7+i(2sqrt(159))/7 ,k= 8/7-i(2sqrt(159))/7