What is the answer to 2x+4(3-2x)=(3(2x+2))/6+4 ?

The answer to 2x+4(3-2x)=(3(2x+2))/6+4 is x=1

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2x+4(3-2x)=(3(2x+2))/6+4

2 x + 4 (3 - 2 x) = \frac{3 ( 2 x + 2 )}{6} + 4

x = 1

Solution steps

2 x + 4 (3 - 2 x) = \frac{3 ( 2 x + 2 )}{6} + 4

Cancel

\frac{3 ( 2 x + 2 )}{6} : \frac{2 x + 2}{2}

2 x + 4 (3 - 2 x) = \frac{2 x + 2}{2} + 4

Multiply both sides by

2

4 x + 8 (3 - 2 x) = 2 x + 10

Expand

4 x + 8 (3 - 2 x) : - 12 x + 24

- 12 x + 24 = 2 x + 10

Move

24

to the right side

- 12 x = 2 x - 14

Move

2 x

to the left side

- 14 x = - 14

Divide both sides by

- 14

x = 1

\frac{1}{4 ^{- 2}}

\frac{4}{3} (3)^{- 2}

5 x - 33 = - 18

(3 + 7 i) (3 - 7 i)

\frac{10}{4} + \frac{3}{5}

What is the answer to 2x+4(3-2x)=(3(2x+2))/6+4 ?
The answer to 2x+4(3-2x)=(3(2x+2))/6+4 is x=1
Solve for x: 2x+4(3-2x)=(3(2x+2))/6+4
The solution is x=1