What are the solutions to the equation 7x^2-5x-1=0 ?

The solutions to the equation 7x^2-5x-1=0 are x=(5+sqrt(53))/(14),x=(5-sqrt(53))/(14)

Find the zeros of 7x^2-5x-1=0

The zeros of 7x^2-5x-1=0 are x=(5+sqrt(53))/(14),x=(5-sqrt(53))/(14)

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7 x^{2} - 5 x - 1 = 0

x = \frac{5 + 53}{14}, x = \frac{5 - 53}{14}

Decimal Notation

x = 0.87715 \dots, x = - 0.16286 \dots

Solution steps

7 x^{2} - 5 x - 1 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 5 ) \pm ( - 5 ) ^{2} - 4 \cdot 7 ( - 1 )}{2 \cdot 7}

(- 5)^{2} - 4 \cdot 7 (- 1) = 53

x_{1, 2} = \frac{- ( - 5 ) \pm 53}{2 \cdot 7}

Separate the solutions

x_{1} = \frac{- ( - 5 ) + 53}{2 \cdot 7}, x_{2} = \frac{- ( - 5 ) - 53}{2 \cdot 7}

x = \frac{- ( - 5 ) + 53}{2 \cdot 7} : \frac{5 + 53}{14}

x = \frac{- ( - 5 ) - 53}{2 \cdot 7} : \frac{5 - 53}{14}

The solutions to the quadratic equation are:

x = \frac{5 + 53}{14}, x = \frac{5 - 53}{14}

h - 8 > 4 h + 5

\frac{x}{x + 1} > 3

x^{2} - 4 x - 140 = 0

- 9 x^{2} - 3 x + 2

6 (x - 7) - 7 (x - 6) = x + 6 - (x - 5)

What are the solutions to the equation 7x^2-5x-1=0 ?
The solutions to the equation 7x^2-5x-1=0 are x=(5+sqrt(53))/(14),x=(5-sqrt(53))/(14)
Find the zeros of 7x^2-5x-1=0
The zeros of 7x^2-5x-1=0 are x=(5+sqrt(53))/(14),x=(5-sqrt(53))/(14)